At Tue, 29 Nov 2011 15:41:30 -0500 Daniel Lieberman <daniel at daniellieberman.org> wrote: > > MIME-Version: 1.0 > > ** Be sure to fill out the survey/skills inventory in the member's area. > ** If you did, we all thank you. > > > > > > Have a perplexing situation. We have 20 megabit down internet service from > Comcast coming in to the front building of our place, gets passed via Cat 5 > probably 150 feet to a patch panel, which distributes it to ethernet ports > in 5 or 6 rooms in the back building. "5 or 6 rooms" == How many ports? How many computers are actually connected to ports? Are there wireless Access Points? If so, how many wireless devices (eg laptops, notbooks, iPads, IPod Touches, etc.) are typically active? > > Why would the connections in the rear building only provide 6-7 megabits? > Could we replace switches or panels in the rear building to provide more > bandwidth to the individual connections? Or is the splitting of the signal > in the rear building the issue? > > Any suggestions? I'm baffled. 20 megabits distributed over 3-4 *active* / *busy* computers yields like 5-6 megabits / computers. A 20 megabit/sec connection means you have only 20 megabits for each second. With one computer (assuming at least a 100BaseT Ethernet card) that *one* computer can sustain a 20 megabit/sec download if (and only if) *no other computer* is doing anything on the LAN. If two computers are doing solid downloads, then they will 'share' the bandwidth. Given that the data is broken up into packets of no more than about 1500 bytes each, the two machines will (more or less) alternate packets. The total packet stream will be about 20 megabit/sec worth (assuming both machines are transfering data to/from 'outside' (rather then with some third computer on the LAN). Roughly 50% of the total packet stream will be for each computer, so each computer will 'see' an effective bandwidth of (about) 10 megabit/sec. With 3 computers, about 33% of the total packet stream will be for each computer, yelding about 6.6666666 megabit/sec per computer. With 4 computers... I think you get the idea. Yes, this assumes ALL of the computers are solidly busy with some big download, all at once. Computers that don't contribute to the total packet stream don't count. But all it takes is *three* totally flat out downloads to bring things down to 6-7 megabits/sec. If you have 10 computers (two per room?), chances are enough of them are busy enough to use up that much bandwidth. > > Daniel > > MIME-Version: 1.0 > > _______________________________________________ > Hidden-discuss mailing list - home page: http://www.hidden-tech.net > Hidden-discuss at lists.hidden-tech.net > > You are receiving this because you are on the Hidden-Tech Discussion list. > If you would like to change your list preferences, Go to the Members > page on the Hidden Tech Web site. > http://www.hidden-tech.net/members > > -- Robert Heller -- 978-544-6933 / heller at deepsoft.com Deepwoods Software -- http://www.deepsoft.com/ () ascii ribbon campaign -- against html e-mail /\ www.asciiribbon.org -- against proprietary attachments